[See] Compute the area of z=2/3(x^3 / 2+y^3 / 2) where (x, y) varies over the unit square: 0 ≤q x ≤q 1,0 ≤q y ≤q
Question: Compute the area of \(z=\frac{2}{3}\left(x^{3 / 2}+y^{3 / 2}\right)\) where \((x, y)\) varies over the unit square: \(0 \leq x \leq 1,0 \leq y \leq 1\)
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[Solution] Let f(x, y)=ll0 \text if y=x^2 , 1 \text if y ≠q x^2
Solution: Consider f(x,
(See Solution) Polynomial approximation works in higher dimensions
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