[Solved] Consider f(x,
Question: Consider
\[f(x, y)=\left\{\begin{array}{cc} \frac{x y\left(x^{2}-y^{2}\right)}{x^{2}+y^{2}} & \text { if }(x, y) \neq(0,0) \\ 0 & \text { if }(x, y)=(0,0) \end{array}\right.\]- Compute \(f_{x}\) and \(f_{y}\). Are the first partial derivatives continuous?
- Show that the mixed second partial derivatives at the origin are not equal, i.e, \(f_{x y} \neq f_{y x}\).
- In reference to Clairaut's Theorem, explain why this is allowed to happen. In other words, why does that theorem fail to apply?
- Using Fubini's theorem, we can prove Clairaut's Theorem. To do so, first argue that if \(f_{x y}\) and \(f_{y x}\) are continuous at a point \((a, b)\) and not equal, then one of them is greater than the other in a square \(S\) about that point.
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Now compute
\[\iint_{S}\left(\frac{\partial^{2} f}{\partial x \partial y}(x, y)-\frac{\partial^{2} f}{\partial y \partial x}(x, y)\right) d A\]
using Fubini's theorem. Why does this give you a contradiction? How does this prove Clairaut's theorem? - Explain how this proof fails for the given function \(f\).
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