Given the probability density function f(x)={ (1)/(20)x^3 1≤ x≤ 3


Question: Given the probability density function

\[f\left( x \right)=\left\{ \begin{aligned} & \frac{1}{20}{{x}^{3}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,1\le x\le 3 \\ & 0\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\text{otherwise} \\ \end{aligned} \right.\]

(a) Find the mean

(b) Find \(p\left( 1.3\le x\le 2.6 \right)\)

Price: $2.99
Solution: The answer consists of 2 pages
Deliverables: Word Document

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