Suppose that the revenue generated by selling x grams of crack is given by R(x)=-1/5x^2+200x. Assume


Question: Suppose that the revenue generated by selling x grams of crack is given by \[R(x)=-\frac{1}{5}{{x}^{2}}+200x\]. Assume that R is in Euros. What is the maximum revenue possible in this situation?

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