Solve 2{{ sin }^3}x-{{ sin }^2}x-2 sin x+1=0 in the interval [0, 2pi)
Question: Solve \[2{{\sin }^{3}}x-{{\sin }^{2}}x-2\sin x+1=0\] in the interval [0, \[2\pi )\]
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Solution: The solution file consists of 1 page
Deliverable: Word Document![](/images/msword.png)
Deliverable: Word Document
![](/images/msword.png)