Explain why the function f(x) = { x^2 - 2 if x does not equal -3, 5 if x = -3 f(x)={
Question: Explain why the function f(x) = { x^2 - 2 if x does not equal -3, 5 if x = -3
\[f\left( x \right)=\left\{ \begin{aligned} & {{x}^{2}}-2\,\,\,\,\,\,\,\,\,x\ne -3 \\ & 5\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,x=3 \\ \end{aligned} \right.\]is discontinuous at the point x = -3. Sketch the graph of the function to show the discontinuity at x = -3.
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Deliverables: Word Document![](/images/msword.png)
Deliverables: Word Document
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