Solution) Let f(x)=∑limits_{n=0}^{∞ }{({{(-1)}^n)/({2)^n}{{x}^n}}{n!}}. Show that f''(x)=4f(x).


Question: Let \(f\left( x \right)=\sum\limits_{n=0}^{\infty }{\frac{{{\left( -1 \right)}^{n}}{{2}^{n}}{{x}^{n}}}{n!}}\). Show that \(f''\left( x \right)=4f\left( x \right)\).

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