(Step-by-Step) Use the following 2 data tables to answer the question Dependent variable is B2:831 No Selector 30 total cases of which one is missing R squared
Question: Use the following 2 data tables to answer the question
| Dependent variable is B2:831 | ||||
| No Selector | ||||
| 30 total cases of which one is missing | ||||
| R squared = 92.4 % R squared adjusted = 92.1 % | ||||
| S= 0.00705 with 29-2=27 degrees of freedom | ||||
| Source | Sum of squares | DF | Mean square | F-Ratio |
| Regression | 2.54195 | 1 | 2.54195 | 329 |
| Residual | 0.200395 | 27 | 0.00771833 | |
| Variable | Coefficient | s.e. of coeff | t-ratio | prob |
| Constant | 0.15803 | 0.04635 | 3.32 | 0.0026 |
| A2:A31 | 0.0650517 | 0.003505 | t 8.1 | Less than or equal to 0.0001 |
| Lower Prediction limit | Upper Prediction limit |
| 0.94522804 | 1.3143816 |
| 1.0730614 | 1.4467549 |
| 0.55473623 | 0.92425344 |
| 0.75130504 | 1.1179946 |
| 0.88088009 | 1.2486262 |
| 0.28864635 | 0.66993 |
| 0.35558105 | 0.73309862 |
| 0.48863252 | 0.86025382 |
| 1.1365571 | 1.5133625 |
| 1.0092869 | 1.380426 |
| 1.0730614 | 1.4467549 |
Finding Prediction interval
For a given tar amount of 17 mg, identify the 95% prediction interval estimate of the amount of nicotine. And write a statement interpreting that interval. (Hint: the bottom of the second display corresponds to the given 17 mg of tar)
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Solution: The downloadable solution consists of 2 pages
Deliverable: Word Document 