Question: Under a standard manufacturing process, the breaking strength of nylon thread is normally distributed, with mean equal to 100 and a standard deviation equal to 5. A new, cheaper process is tested, and a sample of 10 threads is drawn, with the results

105, 95, 95, 99, 98, 97, 101, 100, 100, 99.

Your assistant has noted, “Since the sample mean (standard deviation) is not (is) significantly less than 100 (5) at alpha 0.05, we have strong justification for installing the new process.” Do you agree? Explain!