Find the equation for the tangent plane to the surface z=-6x^2-2y^2 at the point (2, 1, -26).
Question: Find the equation for the tangent plane to the surface \(z=-6{{x}^{2}}-2{{y}^{2}}\) at the point (2, 1, -26).
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Solution Format: Word Document
Solution Format: Word Document
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