Find the interval of convergence: a. ∑limits_{n=1}^{∞ }{({{(-1)}^{n+1})/({5)^{n-3}}}{{{4}
Question: Find the interval of convergence:
a. \[\sum\limits_{n=1}^{\infty }{\frac{{{(-1)}^{n+1}}{{5}^{n-3}}}{{{4}^{n+2}}}}{{(x-1)}^{\begin{smallmatrix}
n+1 \\\end{smallmatrix}}}\]
b. \[\sum\limits_{n=1}^{\infty }{\frac{3\cdot 5\cdot 7\cdot 9\cdot \cdot \cdot (2n+1)}{{{10}^{n}}(2n+1)(n-1)!}}{{(x+5)}^{n}}\]
c. \[\sum\limits_{n=1}^{\infty }{\frac{n{{4}^{n+1}}}{(n+2)!}}{{(x-4)}^{n}}\]
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Solution: The answer consists of 2 pages
Type of Deliverable: Word Document
Type of Deliverable: Word Document
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