Test given series for convergence or divergence. If the series converges and it is possible to find
Question: Test given series for convergence or divergence. If the series converges and it is possible to find the sum, then do so
(a) \(\sum\limits_{n=1}^{\infty }{\frac{1}{n\left( n+1 \right)}}\)
(b) \(\sum\limits_{n=1}^{\infty }{\frac{\ln n}{{{n}^{2}}}}\)
(c) \(\sum\limits_{n=1}^{\infty }{\frac{2{{n}^{2}}+3n}{\sqrt{5+{{n}^{5}}}}}\)
(d) \(\sum\limits_{n=1}^{\infty }{\frac{{{\left( n! \right)}^{2}}}{\left( 3n! \right)}}\)
Price: $2.99
Solution: The solution consists of 3 pages
Deliverables: Word Document
Deliverables: Word Document
