Question: Suppose you throw a baseball straight up at a velocity of 64 feet per second. A function can be created by expressing distance above the ground, s, as a function of time, t. This function is s = -16t² + v₀t + s₀

16 represents 1/2g, the gravitational pull due to gravity (measured in feet per second²).

v₀ is the initial velocity (how hard do you throw the object, measured in feet per second).

s₀ is the initial distance above ground (in feet). If you are standing on the ground, then s₀ = 0.

a) What is the function that describes this problem?

b) The ball will be how high above the ground after 1 second?

c) How long will it take to hit the ground?

d) What is the maximum height of the ball? What time will the maximum height be attained?