Solution) The position of a vector of a particle at time t is x(t)=(√{2} cos t, sin t, sin t)


Question: The position of a vector of a particle at time t is

\[x\left( t \right)=\left( \sqrt{2}\cos t,\sin t,\sin t \right)\]

(a) Find the velocity

(b) Find the acceleration

(c) Show that the acceleration is always perpendicular to the velocity vector.

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See Solution: The solution consists of 1 page
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