Solution) The position of a vector of a particle at time t is x(t)=(√{2} cos t, sin t, sin t)
Question: The position of a vector of a particle at time t is
\[x\left( t \right)=\left( \sqrt{2}\cos t,\sin t,\sin t \right)\](a) Find the velocity
(b) Find the acceleration
(c) Show that the acceleration is always perpendicular to the velocity vector.
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See Solution: The solution consists of 1 page
Deliverables: Word Document
Deliverables: Word Document
