Solutions Calculus

Find the area of the surface of the portion of the cone x^2+y^2=z^2 between the cylinder

Question: Problem #4: Find the area of the surface of the portion of the cone \({{x}^{2}}+{{y}^{2}}={{z}^{2}}\) between the cylinder \({{y}^{2}}=x\) and the plane \(x-y=2\).

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Solution: The solution consists of 2 pages
Deliverables: Word Document

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