Solutions Algebra Evaluate (b^2-c)/(ab+c) a = 2, b = -3, and c = -1. Question: Evaluate \[\frac{{{b}^{2}}-c}{ab+c}\] a = 2, b = –3, and c = –1. Price: $2.99 Solution: The solution consists of 1 pageDeliverable: Word Document ∴ Other downloads you may be interested in ∴ [Solved] Evaluate: {{(a-4b)}^2}÷ {c^3} when a=4, b=-1, c=-2 #29323 (See Solution) Re-write in simplified radical form (assume all variables represent real positive numbers) #14947 (Solved) Factor: x^2-x-12 #29292 Algebra - Solving equations reducing expressions and factoring #29322 Math Solutions Math and Statistics Answers