Solve the equation: 2w(4w+1)=1 x^2-36=0 x^2=4x {{(x-3)}^2}+{{(x+2)}^2}=17
Question: Solve the equation:
\[2w\left( 4w+1 \right)=1\]
\[{{x}^{2}}-36=0\]
\[{{x}^{2}}=4x\]
\[{{\left( x-3 \right)}^{2}}+{{\left( x+2 \right)}^{2}}=17\]
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Solution: The downloadable solution consists of 1 page
Deliverables: Word Document
Deliverables: Word Document
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