Solve by first rewriting as a quadratic equation: {{x}^{{}^2!_{3};}}-7{{x}^{{}^1!_{3};}}+12=0


Question: Solve by first rewriting as a quadratic equation: \[{{x}^{{}^{2}\!\!\diagup\!\!{}_{3}\;}}-7{{x}^{{}^{1}\!\!\diagup\!\!{}_{3}\;}}+12=0\]

Price: $2.99
Solution: The solution consists of 1 page
Type of Deliverable: Word Document

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