(Solved) Use the results of 2 and 3 to find Cov;(3 X+2 Y, 5 Z-W) where Cov;(X, Z)=2 Cov;(X, W)=4 Cov;(Y, Z)=1 Cov;(Y,
Question: Use the results of 2 and 3 to find \(\operatorname{Cov}(3 X+2 Y, 5 Z-W)\) where \(\operatorname{Cov}(X, Z)=2\)
\(\operatorname{Cov}(X, W)=4\)
\(\operatorname{Cov}(Y, Z)=1\)
\(\operatorname{Cov}(Y, W)=10\)
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