(See) Let B(x):=-1/2 x^2 for x<0 and B(x):=1/2 x^2 for x ≥q 0. Show that ∫_a^b|x| d
Question: Let \(B(x):=-\frac{1}{2} x^{2}\) for \(x<0\) and \(B(x):=\frac{1}{2} x^{2}\) for \(x \geq 0\). Show that \(\int_{a}^{b}|x| d x=B(b)-B(a)\).
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