Solution: Prove that
Question: Prove that
\[{{s}^{2}}=\frac{1}{n-1}\sum\limits_{i=1}^{n}{{{\left( {{x}_{i}}-\bar{x} \right)}^{2}}}=\frac{1}{n-1}\left( \sum\limits_{i=1}^{n}{x_{i}^{2}}-\frac{1}{n}{{\left( \sum\limits_{i=1}^{n}{{{x}_{i}}} \right)}^{2}} \right)\]
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