[Steps Shown] Solve the following inequalities: |7x-8|≤ 4x+7 (x+1)^2>0 (3x)/(2x^2+18)<0 2x^2+2x-3 (2x-3)/(5)≥
Question: Solve the following inequalities:
- \(|7x-8|\le 4x+7\)
- \({{\left( x+1 \right)}^{2}}>0\)
- \(\frac{3x}{2{{x}^{2}}+18}<0\)
- \(2{{x}^{2}}+2x-3<{{x}^{2}}+7x+3\)
- \(\frac{2x-3}{5}\ge \frac{x}{2}\)
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Solution: The downloadable solution consists of 2 pages
Deliverable: Word Document 