Question: Social activities for students: As part of her class project, a student at the Univ. of Florida randomly sampled 10 fellow students to investigate their most common social activities. As part of the study, she asked the students to state how many times they had done each of the following activities during the previous year: going to a movie, going to a sporting event, or going to a party. The table shows the data.

Frequency of attending movies, sports events, and parties :

ACTIVITY

Student Movies Sports Parties

1 10 5 25

2 4 0 10

3 12 20 6

4 2 6 52

5 12 2 12

6 7 8 30

7 45 12 52

8 1 25 2

9 25 0 25

_ 10 12 12 4__

The output shows the result of comparing the mean responses on parties and sports.

Paired T for Parties - Sports

N Mean St.Dev. SE Mean

Parties 10 21.8000 18.5760 5.8742

Sports 10 9.0000 8.3799 2.6499

Difference 10 12.8000 22.5477 7.1302

95% CI for mean difference: (-3.3297, 28.9297)

T-Test of mean difference = 0 (vs not = 0)

T-Value = 1.80 P-Value = 0.106

1. Explain how to interpret the reported 95% confidence interval.
2. State the hypotheses to which the P-value refers, and interpret its value.
3. Explain the connection between the results of the test and the confidence interval.
4. What assumptions are necessary for these inferences to be appropriate?

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Solution: The downloadable solution consists of 2 pages
Deliverable: Word Document