[Solution] Show if Z is any random variable then Cov;(X+Y, Z)=Cov;(X, Z)+Cov;(Y,


Question: Show if \(Z\) is any random variable then \(\operatorname{Cov}(X+Y, Z)=\operatorname{Cov}(X, Z)+\operatorname{Cov}(Y, Z)\)

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Solution: The downloadable solution consists of 1 pages
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