[Solution] A researcher reported that a sample of size n=30 produced a sample mean of 32.56% and a sample standard deviation of 6.56%. Use this information
Question: A researcher reported that a sample of size n=30 produced a sample mean of 32.56% and a sample standard deviation of 6.56%. Use this information to calculate a 90% confidence interval for the national average for the "percent of low-income working families". Provide the upper and lower limits of the confidence interval and the margin of error. (Round the limits to two decimal places.)
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