[Solved] A random sample of 365 medical doctors showed that 132 had a solo practice. Find a 90% confidence interval for the true proportion of all medical
Question: A random sample of 365 medical doctors showed that 132 had a solo practice. Find a 90% confidence interval for the true proportion of all medical doctors who have a solo practice.
- Find p-hat the point estimate for the true proportion (round to 2 decimal places)
- Now, calculate confidence interval (you may use your calculator)
- What would the margin of error be for this problem
- Write an interpretive sentence for the interval found above
- Find the sample size necessary for a 99% confidence level with a maximum error of estimate E = 2%., using the value of p-hat that you calculated above for the preliminary estimate of p.
- Find the sample size necessary for a 99% confidence level with a maximum error of estimate E = 2%., when there is no initial estimate of p.
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