[See Solution] Prove the following identity: (tan θ + sec ^2theta -1)/(tan θ - sec)^2theta +1=(cos θ + sin θ)/(cos θ


Question: Prove the following identity:

\[\frac{\tan \theta +{{\sec }^{2}}\theta -1}{\tan \theta -{{\sec }^{2}}\theta +1}=\frac{\cos \theta +\sin \theta }{\cos \theta -\sin \theta }\]

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Solution: The downloadable solution consists of 1 pages
Deliverable: Word Document

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