[Solution] A prisoner must place ten while balls and ten black balls in two boxes. The jailer will draw one ball from one of the two boxes. If the ball is
Question:
- A prisoner must place ten while balls and ten black balls in two boxes. The jailer will draw one ball from one of the two boxes. If the ball is white, the prisoner will be released. If the ball is black, another then years will be added to his sentence. How should the prisoner place the balls in the boxes to ensure the nest chance of freedom? What is the maximum probability of drawing a white ball?
- A bag contains small straws of the following lengths: 2 cm, 3 cm, 5 cm, 7 cm, 11 cm, and 13 cm. Three straws are drawn at random. What is the probability that a triangle can be formed with the straws that are drawn?
- In a three game playoff series, the probability that team A will win each game is twice the probability that team B will win. What is the probability that team B will win the series?
- An ordinary fifty-card deck is divided into two unequal portions A and B in such a way that the probability that a card drawn from portion A is red is 1/3. If a red card is transferred from portion A to portion B, the probability that a card drawn from portion B is black is 1/3. How was the pack originally divided?
- Continue problem (d) using portions A and B as the deck was originally divided. Suppose that a card is randomly drawn from portion A and added to portion B, and then a card is randomly drawn from portion B. Find the probability that the card drawn from B is black.
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