(All Steps) The position of a vector of a particle at time t is x(t)=(√2 cos t, sin t, sin t) Find the velocity Find the acceleration Show that the


Question: The position of a vector of a particle at time t is

\[x\left( t \right)=\left( \sqrt{2}\cos t,\sin t,\sin t \right)\]
  1. Find the velocity
  2. Find the acceleration
  3. Show that the acceleration is always perpendicular to the velocity vector.

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Solution: The downloadable solution consists of 1 pages
Deliverable: Word Document

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