Solution: (a) Find the point of intersection of the lines (x-1)/(2)=(y+1)/(1)=(z-1)/(-2) (x+2)/(-7)=(y-11)/(10)=(z+6)/(-3) (b) Find a vector perpendicular
Question: (a) Find the point of intersection of the lines
\[\frac{x-1}{2}=\frac{y+1}{1}=\frac{z-1}{-2}\] \[\frac{x+2}{-7}=\frac{y-11}{10}=\frac{z+6}{-3}\](b) Find a vector perpendicular to both lines
(c) Find the equation of the plane containing both lines
Deliverable: Word Document 
Solution: (a) Find an classify all the critical points of f(x,y)=x^2+y^2+xy+x
![[See Solution] Let f(x,y)=(x+y)/(xy) Find ∇ f](/images/solutions/MC-solution-library-45180.jpg "[See Solution] Let f(x,y)=(x+y)/(xy) Find ∇ f Find the directional")
[See Solution] Let f(x,y)=(x+y)/(xy) Find ∇ f Find the directional
![[Steps Shown] Using spherical coordinates find the](/images/solutions/MC-solution-library-45181.jpg "[Steps Shown] Using spherical coordinates find the volume of the")
[Steps Shown] Using spherical coordinates find the volume of the
(See Steps) Find the area of that portion of the plane 2x+3y-z+7=0
![[All Steps] Let z=f(u,v) where u=x^2-y^2, and](/images/solutions/MC-solution-library-45183.jpg "[All Steps] Let z=f(u,v) where u=x^2-y^2, and v=2xy. If z_uu+z_vv=0,")
[All Steps] Let z=f(u,v) where u=x^2-y^2, and v=2xy. If z_uu+z_vv=0,
Solving Absolute Value Inequalities - MathCracker.com