[Solved] Part II: Confidence Interval To construct a 90% confidence interval for the proportion (percentage) of homes in your state that have an advertised
Question:
Part II: Confidence Interval
To construct a 90% confidence interval for the proportion (percentage) of homes in your state that have an advertised selling price of over $300000, we first need an estimate for the population proportion.
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Using your original (untrimmed) sample, state the value of p-hat. (See the table constructed in Part 6 of your spreadsheet in order to help you calculate p-hat.)
^
p is read p-hat.
(Notice the hat "^" on top of the letter p, although it should be directly on top instead of so high above the letter p, indicates that this is the sample proportion of successes.) - Using the value you calculated for p-hat for your state, are n times p-hat and n times q-hat both greater than or equal to 5? Note that n is your sample size.
- If your answer to part b is yes, then construct the 90% confidence interval for p, the population proportion of homes in your state that have an advertised selling price of over $300,000. If your answer to part b is no, then you cannot use the normal distribution to approximate the binomial distribution, but please try constructing the CI using the normal distribution to ensure that you understand how to construct a confidence interval even though the interval that you will construct in this case, using the normal distribution when the normal distribution is not appropriate, is misleading and considered a misuse/abuse of statistics.
- Write an interpretation (that is, determine a reasonable inference and prediction that then could be used to make appropriate decisions) for the confidence interval you constructed in the context of the prices.
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