[See] If P(A)=0.65, P(B)=0.76 and P(A ∩ B)=0.80 then P(A ∪ B) is 0.65. 0.61. 0.80.
Question: If \(P(A)=0.65, P(B)=0.76\) and \(P(A \cap B)=0.80\) then \(P(A \cup B)\) is
- 0.65.
- 0.61.
- 0.80.
- 0.02.
Deliverable: Word Document 
(See Solution) Two events A and B are said to mutually exclusive
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