(See Steps) Let S 1=(x, y) ∈ \Re^2 \mid y=x and S 2=(x, y) ∈ \Re^2 \mid y=2 x. Show that $S 1, S 2$ and S 1 ∩ S 2 are subspaces of \Re^2,
Question: Let \(S 1=\left\{(x, y) \in \Re^{2} \mid y=x\right\}\) and \(S 2=\left\{(x, y) \in \Re^{2} \mid y=2 x\right\}\). Show that $S 1, S 2$ and \(\mathrm{S} 1 \cap S 2\) are subspaces of \(\Re^{2}\), but \(S 1 \cup S 2\) is not a subspace of \(\mathfrak{R}^{2}\).
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![[Steps Shown] Let A be n x](/images/solutions/MC-solution-library-75171.jpg "[Steps Shown] Let A be n x n matrix. Prove that if A is invertible")
[Steps Shown] Let A be n x n matrix. Prove that if A is invertible
Solution: Let B= 1-3x^2+2x^3,x+2x^2-3x^3,1-3x-8x^2+7x^3,2+x-5x^2+5x^3
(Solution Library) Let A and B are both n x n matrices, suppose that
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[Solution Library] Let T:R^3→ R^2 be a linear transformation, and
(See Steps) Let T:R^3→ R^3 be a linear transformation. Let
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