[Solved] The height of a rock is thrown up from ground level is given by h(t)=-16t^2+40t, where h is in feet and t is in seconds How high does the rock
Question: The height of a rock is thrown up from ground level is given by \(h(t)=-16{{t}^{2}}+40t\), where h is in feet and t is in seconds
- How high does the rock go?
- How long does it take for it to return to the ground?
- What is its velocity just before hitting the ground?
Deliverable: Word Document 
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