(Solved) The heat evolved in calories per gram of a cement mixture is approximately normally distributed. The mean is thought to be 100 and the standard
Question: The heat evolved in calories per gram of a cement mixture is approximately normally distributed. The mean is thought to be 100 and the standard deviation is 2. We wish to test \({{H}_{0}}:\mu =100\) versus \({{H}_{1}}:\mu \ne 100\) with a sample of n = 9 specimens.
- If the acceptance region in defined as \(98.5\le \bar{X}\le 101.5\), find the type I error probability \(\alpha \).
- Find \(\beta \) for the case that the true mean heat evolved is 103
- Find \(\beta \) for the case where the true mean heat evolved is 105. This value of \(\beta \) is smaller than the one found in part (b), why?
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