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[Steps Shown] The gravitational potential energy of an object at height h above the surface of Earth is -G M (m)/((r+h)), where R is the radius of Earth. What is

Question: The gravitational potential energy of an object at height $h$ above the surface of Earth is $-G M \frac{m}{(r+h)}$, where $R$ is the radius of Earth. What is the difference between the potential at this point and a point on the surface of Earth (which has potential $-G M \frac{m}{R}$ ) ? Assume $R$ is much, much bigger than $h$.

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[Steps Shown] The gravitational potential energy of an object at height h above the surface of Earth is -G M (m)/((r+h)), where R is the radius of Earth. What is

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