[Solution] The graph of y=f(x) is given below lim _x \rightarrow 3 f(x)= lim _x \rightarrow 6^- f(x)= lim _x \rightarrow 1 f(x)= lim _x \rightarrow 5^-


Question: The graph of \(y=f\left( x \right)\) is given below

\(\lim _{x \rightarrow 3} f(x)=

\lim _{x \rightarrow 6^{-}} f(x)=\) \(\lim _{x \rightarrow 1} f(x)=\)

\(\lim _{x \rightarrow 5^{-}} \frac{4}{f(x)}=\)

\(\lim _{x \rightarrow 0} e^{f(x)}=\)

\(\lim _{x \rightarrow-8} \frac{x^{2}}{f(x)}=\)

\(f'(2)=\)

\(\underset{x\to -{{1}^{-}}}{\mathop{\lim }}\,\frac{f(x)-f(-1)}{x+1}=\)

\(\lim _{x \rightarrow-7} \frac{f(x)-f(-7)}{x+7}=\)

\(\lim _{h \rightarrow 0^{+}} \frac{f(-3+h)-f(-3)}{h}=\)

State one specific value of \(x\) where \(f\) is continuous from the left but not continuous from the right.

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Solution: The downloadable solution consists of 3 pages
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