(See Solution) Find ∫_0^3 f(x) d x without the use of limits, where f(x)= \begincases2 \text if 0 ≤q x<1 , 2-x \text if 1 ≤q x ≤q 2 , -1+x/2 \text
Question: Find \(\int_{0}^{3} f(x) d x\) without the use of limits, where
\[f(x)= \begin{cases}2 & \text { if } 0 \leq x<1 \\ 2-x & \text { if } 1 \leq x \leq 2 \\ -1+\frac{x}{2} & \text { if } x>2\end{cases}\]
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