(Solution Library) Find an equation of the line that is tangent to the graph of f for the given value of x. f(x)=(x^2-3)^5(2 x-1)^3 ;


Question: Find an equation of the line that is tangent to the graph of f for the given value of x.

\(f(x)=\left(x^{2}-3\right)^{5}(2 x-1)^{3} ; x=2\)

Price: $2.99
Solution: The downloadable solution consists of 1 pages
Deliverable: Word Document

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