Math Solutions

Solution: Find the absolute maximum and absolute minimum of f(x) on the given closed interval. f(x)=5+|6-3x|, [ 1,5 ] f(x)=(2x)/(x^2+1), [ 0,7

Question: Find the absolute maximum and absolute minimum of f(x)f\left( x \right) on the given closed interval.

  1. f(x)=5+∣6−3x∣,   [1,5]f\left( x \right)=5+|6-3x|,\,\,\,\left[ 1,5 \right]
  2. f(x)=2xx2+1,   [0,7]f\left( x \right)=\frac{2x}{{{x}^{2}}+1},\,\,\,\left[ 0,7 \right]

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