[See Solution] Demand: Find the demand function x = f (p) that satisfies the initial conditions. (d x)/(d p)=-(6000 p)/((p^2-16)^3 / 2), x = 5000 when p
Question: Demand: Find the demand function x = f ( p ) that satisfies the initial conditions.
\(\frac{d x}{d p}=-\frac{6000 p}{\left(p^{2}-16\right)^{3 / 2}}\), x = 5000 when p = $5.
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