[Steps Shown] The curve C is parameterized by x[t], y[t], z[t]=2 t^2, 2 ÷ t^2, 1-t^2 with 0 ≤q t ≤q 2 This tells you that C starts at 0,2,1

Question: The curve $\mathrm{C}$ is parameterized by

\[\{x[t], y[t], z[t]\}=\left\{2 t^{2}, 2 \div t^{2}, 1-t^{2}\right\}\]

with $0 \leq t \leq 2$

This tells you that C starts at $\{0,2,1\}$ and ends at $\{8,6,-3\}$.

Measure the flow of the $3 \mathrm{D}$ vector field

Field $[x, y, z]=\{z, y, x\}$

along $\mathrm{C}$ and interpret the result.

Use hand calculation to determine whether the net flow of Field[x, y, z] along $C$ is in the direction of the parameterization, or against the direction of the parameterization.

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Solution: The downloadable solution consists of 1 pages
Deliverable: Word Document

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[Steps Shown] The curve C is parameterized by x[t], y[t], z[t]=2 t^2, 2 ÷ t^2, 1-t^2 with 0 ≤q t ≤q 2 This tells you that C starts at 0,2,1

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