[Solution Library] The centripetal acceleration of a particle moving in a circle is a=(v^2)/(r), where v is the velocity and r is the radius. Approximate the
Question: The centripetal acceleration of a particle moving in a circle is \(a=\frac{{{v}^{2}}}{r}\), where v is the velocity and r is the radius. Approximate the maximum percent error in measuring the acceleration due to errors of 3% in v and 2% in r .
Deliverable: Word Document 
![[Step-by-Step] Compute (dw)/(dt) using the Chain rule:](/images/solutions/MC-solution-library-47399.jpg "[Step-by-Step] Compute (dw)/(dt) using the Chain rule: w=√x^2+y^2")
[Step-by-Step] Compute (dw)/(dt) using the Chain rule: w=√x^2+y^2
![[Step-by-Step] For w= cos (x-y) , x=t^2,y=1](/images/solutions/MC-solution-library-47400.jpg "[Step-by-Step] For w= cos (x-y) , x=t^2,y=1 , Compute (dw)/(dt) using")
[Step-by-Step] For w= cos (x-y) , x=t^2,y=1 , Compute (dw)/(dt) using
![[Solution Library] Find (∂ w)/(∂ s) and](/images/solutions/MC-solution-library-47401.jpg "[Solution Library] Find (∂ w)/(∂ s) and (∂ w)/(partial t)")
[Solution Library] Find (∂ w)/(∂ s) and (∂ w)/(partial t)
![[All Steps] Find (∂ w)/(∂ s) and](/images/solutions/MC-solution-library-47402.jpg "[All Steps] Find (∂ w)/(∂ s) and (∂ w)/(partial t)")
[All Steps] Find (∂ w)/(∂ s) and (∂ w)/(partial t)
(Solution Library) Find (∂ w)/(∂ r) and (∂ w)/(partial
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