Solutions Algebra

Suppose ∫{f(u)du}=F(u)+C. Show that ∫{f(ax+b)dx}=(1)/(a)F(ax+b)+C

Question: Suppose \(\int{f\left( u \right)du}=F\left( u \right)+C\). Show that \(\int{f\left( ax+b \right)dx}=\frac{1}{a}F\left( ax+b \right)+C\)

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