Question: Given

\[A=\left[ \begin{matrix} 1 & -3 & 2 \\ 2 & 1 & -3 \\ 4 & -3 & -1 \\ \end{matrix} \right],\text{ }B=\left[ \begin{matrix} 1 & \text{4} & \text{1} \\ 2 & \text{1} & \text{1} \\ 1 & -2 & \text{1} \\ \end{matrix}\text{ }\begin{matrix} 0 \\ 1 \\ 2 \\ \end{matrix} \right],\text{ }C=\left[ \begin{matrix} 2 & \text{1} & -1 \\ 3 & -2 & -1 \\ 2 & -5 & -1 \\ \end{matrix}\text{ }\begin{matrix} -2 \\ -1 \\ 0 \\ \end{matrix} \right]\] show that \(AB=AC\). What general conclusion can be drawn from this example?