[Solved] You are walking around a closed curve C with no loops (a curve like a distorted circle) in the counterclockwise way, and at time t, you are at
Question: You are walking around a closed curve \(C\) with no loops (a curve like a distorted circle) in the counterclockwise way, and at time \(\mathrm{t}\), you are at the point \(\{\mathrm{x}[\mathrm{t}], \mathrm{y}[\mathrm{t}]\}\).
The unit normal vector
\[\text { outerunitnormal }[\mathrm{t}]=\frac{\left(y^{\prime}[t],-x^{\prime}(t)\right]}{\sqrt{x^{\prime}[t]^{2}+y^{\prime}(t]^{2}}}\]with tail at \(\{x[t], y[t]\}\) points out away from the curve toward your right foot. When you use this unit normal to measure the flow of a vector field
Field \([x, y]=\{m[x, y], n[x, y]\}\)
across C, you calculate
\[\text{(Tex translation failed)}\] F.outerunitnormal \(d \mathrm{~s}\)How do you interpret the result if
\[\oint_{\mathrm{C}}-\mathrm{n}[\mathrm{x}, \mathrm{y}] d \mathrm{x}+\mathrm{m}[\mathrm{x}, \mathrm{y}] d \mathrm{y}>0 ?\]
Deliverable: Word Document 