Question: Using only definition: A sequence, t, converges to the real number s provided that for each r > 0 there exists a real number N such that for all n an element of N, n>N implies that the absolute value of |t-s|  < r.  If t converges, then s is called the limit of the sequence t.  If a sequence does not converge to a real number it is said to diverge.

Prove the following:

1. For any real number k>0, the limit as n approaches infinity, of 1/n^k = 0
2. \(\underset{n\to \infty }{\mathop{\lim }}\,\frac{3n+1}{n+2}=3\)
3. \(\underset{n\to \infty }{\mathop{\lim }}\,\frac{\sin n}{n}=0\)
4. \(\underset{n\to \infty }{\mathop{\lim }}\,\frac{n+2}{{{n}^{2}}-3}=0\)

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