[See] Use substitution y=x^r to find the general solution to the given equation for x>0 :
Question: 5: Use substitution \(y={{x}^{r}}\) to find the general solution to the given equation for \(x>0\) :
\[\frac{{{d}^{2}}y}{d{{x}^{2}}}=\frac{5}{x}\frac{dy}{dx}-\frac{13}{{{x}^{2}}}y\]
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