[See Steps] Use differentials or the linearization of the function f(, y)=e^x^2-1 to approximate the 1.99^2-4.02 number C^n. Show your calculus
Question: Use differentials or the linearization of the function \(f(, y)=e^{x^{2}-1}\) to approximate the \(1.99^{2}-4.02\)
number \(\mathrm{C}^{\mathrm{n}}\). Show your calculus work!
Deliverable: Word Document 
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