(Steps Shown) A town has two supermarkets, one named W and one named S. Each month 70% of the customers of W stick with W and 30% switch to S: Each month


Question: A town has two supermarkets, one named W and one named S. Each month 70% of the customers of W stick with W and 30% switch to S: Each month 80% of the customers of S stick with S and 20% switch to W: The total number of customers stays constant from month to month. Let \(w\left( n \right);s\left( n \right)\) denote the number of customers of W, S during month n. Find a matrix

\[M=\left( \begin{matrix} a & b \\ c & d \\ \end{matrix} \right)\]

so that

\[\left( \begin{matrix} w\left( n+1 \right) \\ s\left( n+1 \right) \\ \end{matrix} \right)=\left( \begin{matrix} a & b \\ c & d \\ \end{matrix} \right)\left( \begin{matrix} w\left( n \right) \\ s\left( n \right) \\ \end{matrix} \right)\]

Assume w(0) = 100; s(0) = 50. Compute, using M, the number of customers in month 1 of S, W; that is, compute w(1), s(1):

Price: $2.99
Solution: The downloadable solution consists of 1 pages
Deliverable: Word Document

log in to your account

Don't have a membership account?
REGISTER

reset password

Back to
log in

sign up

Back to
log in